Golang | Leetcode Golang题解之第295题数据流的中位数
题目：
题解：
type MedianFinder struct {nums *redblacktree.Treetotal intleft, right iterator
}func Constructor() MedianFinder {return MedianFinder{nums: redblacktree.NewWithIntComparator()}
}func (mf *MedianFinder) AddNum(num int) {if count, has := mf.nums.Get(num); has {mf.nums.Put(num, count.(int)+1)} else {mf.nums.Put(num, 1)}if mf.total == 0 {it := mf.nums.Iterator()it.Next()mf.left = iterator{it, 1}mf.right = mf.left} else if mf.total%2 == 1 {if num < mf.left.Key().(int) {mf.left.prev()} else {mf.right.next()}} else {if mf.left.Key().(int) < num && num < mf.right.Key().(int) {mf.left.next()mf.right.prev()} else if num >= mf.right.Key().(int) {mf.left.next()} else {mf.right.prev()mf.left = mf.right}}mf.total++
}func (mf *MedianFinder) FindMedian() float64 {return float64(mf.left.Key().(int)+mf.right.Key().(int)) / 2
}type iterator struct {redblacktree.Iteratorcount int
}func (it *iterator) prev() {if it.count > 1 {it.count--} else {it.Prev()it.count = it.Value().(int)}
}func (it *iterator) next() {if it.count < it.Value().(int) {it.count++} else {it.Next()it.count = 1}
}