C++ | Leetcode C++题解之第401题二进制手表
题目：
题解：
class Solution {
public:vector<string> readBinaryWatch(int turnedOn) {vector<string> ans;for (int i = 0; i < 1024; ++i) {int h = i >> 6, m = i & 63; // 用位运算取出高 4 位和低 6 位if (h < 12 && m < 60 && __builtin_popcount(i) == turnedOn) {ans.push_back(to_string(h) + ":" + (m < 10 ? "0" : "") + to_string(m));}}return ans;}
};