力扣用例题:2的幂
此题的解题方法在于根据用例调整代码
bool isPowerOfTwo(int n) {if(n==1){return true;}if(n<=0){return false;}while(n>2){if(n%2==1){return false;}n=n/2; }if(n==1){return false;}return true;}
此题的解题方法在于根据用例调整代码
bool isPowerOfTwo(int n) {if(n==1){return true;}if(n<=0){return false;}while(n>2){if(n%2==1){return false;}n=n/2; }if(n==1){return false;}return true;}