递归算法 分析json字符串，自制简易表达式
json实例
{"success": true,"code": 200,"message": "调用成功","data": {"nodeResults": [{"success": true,"result": {"success": true,"score": 240.0,"hitRules": [{"success": true,"score": 60.0}, {"success": true,"score": 61.0}, {"success": true,"score": 66.0}, {"success": true,"score": 610.0}]}}, {"success": true,"result": {"success": true,"score": 120.0,"hitRules": [{"success": true,"score": 50.0}, {"success": true,"score": 90.0}]}}]}
}现在要获取score的值，路径为data->nodeResults->result->hitRules->score
采用递归算法，层层分析json，自定义一个简单的表达式，对象就直接写属性名，数组的属性名后面加上[]
data.nodeResults[].result.hitRules[].score算法代码如下：
private static void analysisJSON(String el,String json){String[] els = el.split("\\.");JSONArray array ;JSONObject jsonObject;String s = "";if(els.length==1){ s = el;}else {for (int i = 1; i < els.length; i++) {s = s + els[i] + ".";}}if("".equals(s)) return;JSONObject temp = new JSONObject();if (els.length==0) return;if(els[0].endsWith("[]")){jsonObject = JSONObject.parseObject(json);if(jsonObject.get(els[0].substring(0,els[0].length()-2))!=null) {array = JSONArray.parseArray(jsonObject.get(els[0].substring(0, els[0].length() - 2)).toString());for (int i = 0; i < array.size(); i++) {analysisJSON(s.substring(0, s.length() - 1), ((JSONObject) array.get(i)).toJSONString());}}}else {try {jsonObject = JSONObject.parseObject(json);if (jsonObject.get(els[0]) != null) {if(els.length==1) {System.out.println("已找到匹配的字段------>"+jsonObject.get(els[0]).toString());}else{analysisJSON(s.substring(0, s.length() - 1), jsonObject.get(els[0]).toString());}}}catch (Exception e){}}}main方法调用端：
public static void main(String[] args) {String text = "";//json内容analysisJSON("data.nodeResults[].result.hitRules[].score",text );}运行结果如下：
已找到匹配的字段------>60.0
已找到匹配的字段------>61.0
已找到匹配的字段------>66.0
已找到匹配的字段------>610.0
已找到匹配的字段------>50.0
已找到匹配的字段------>90.0