C语言 | Leetcode C语言题解之第415题字符串相加
题目：
题解：
char* addStrings(char* num1, char* num2) {int i = strlen(num1) - 1, j = strlen(num2) - 1, add = 0;char* ans = (char*)malloc(sizeof(char) * (fmax(i, j) + 3));int len = 0;while (i >= 0 || j >= 0 || add != 0) {int x = i >= 0 ? num1[i] - '0' : 0;int y = j >= 0 ? num2[j] - '0' : 0;int result = x + y + add;ans[len++] = '0' + result % 10;add = result / 10;i--, j--;}// 计算完以后的答案需要翻转过来for (int i = 0; 2 * i < len; i++) {int t = ans[i];ans[i] = ans[len - i - 1], ans[len - i - 1] = t;}ans[len++] = 0;return ans;
}