python输入半径计算公式_python练习：取输入半径的周长和面积
1楼：tim_spac 发表于 2014-07-23 14:57
import math
PI = math.pi
def getInteger(prompt="Enter an integer: ",
failprompt="Input should be an integer.",
default=None,
checker=None,
):
while 1:
try:
got = int(raw_input(prompt) or default)
if checker is None or \
(callable(checker) and checker(got)) or \
(isinstance(checker, set) and got in checker) or \
(isinstance(checker, tuple)
and len(checker)==2
and checker[0] <= got <= checker[1]):
return got
print(failprompt)
except:
print(failprompt)
class Circle:
def __init__(self, radiu):
self.radiu = radiu
def area(self):
return self.radiu ** 2 * PI
def circumference(self):
return 2 * PI * self.radiu
def __getIntegerTester__():
code = getInteger("Enter code:")
print("we got your code: %d" % code)
year_range = (1970, 2199)
year = getInteger("Enter year:",
checker=year_range,
default=2014,
failprompt="year should between between %d ~ %d" % year_range
)
print("we got your year: %d" % year)
month = getInteger("Enter month:",
checker=lambda x: (1 <= x <= 12),
failprompt="the month should an integer between 1 and 12")
print("we got your month: %d" % month)
categories = set(range(5))
category = getInteger("Enter category id:",
checker=categories ,
failprompt="the category should in set %r" % categories )
print("we got your category: %d" % category)
if __name__ == "__main__":
while 1:
radiu = getInteger()
if radiu <= 0:
break
circle = Circle(radiu)
print "The circumference is: %.2f, the area is: %.2f" % (
circle.circumference(), circle.area()
)