本作业要求来自于:https://edu.cnblogs.com/campus/gzcc/GZCC-16SE1/homework/2684
1.字符串操作:
解析身份证号:生日、性别、出生地等。
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code
=
input
(
"请输入您的身份证号:"
);
year
=
code[
6
:
10
];
month
=
code[
10
:
12
];
day
=
code[
12
:
14
];
province
=
code[
0
:
2
];
area
=
{
'11'
:
'北京市'
,
'12'
:
'天津市'
,
'13'
:
'河北省'
,
'14'
:
'山西省'
,
'15'
:
'内蒙古自治区'
,
'21'
:
'辽宁省'
,
'22'
:
'吉林省'
,
'23'
:
'黑龙江省'
,
'31'
:
'上海市'
,
'32'
:
'江苏省'
,
'33'
:
'浙江省'
,
'34'
:
'安徽省'
,
'35'
:
'福建省'
,
'36'
:
'江西省'
,
'37'
:
'山东省'
,
'41'
:
'河南省'
,
'42'
:
'湖北省'
,
'43'
:
'湖南省'
,
'44'
:
'广东省'
,
'45'
:
'广西壮族自治区'
,
'46'
:
'海南省'
,
'50'
:
'重庆市'
,
'51'
:
'四川省'
,
'52'
:
'贵州省'
,
'53'
:
'云南省'
,
'54'
:
'西藏自治区'
,
'61'
:
'陕西省'
,
'62'
:
'甘肃省'
,
'63'
:
'青海省'
,
'64'
:
'宁夏回族自治区'
,
'65'
:
'新疆维吾尔自治区'
,
'71'
:
'台湾省'
,
'81'
:
'香港特别行政区'
,
'82'
:
'澳门特别行政区'
}
print
(
"你所查询的身份证归属地为:"
+
area.get(province));
print
(
"出生日期是{}年{}月{}日"
.
format
(year,month,day));
sex
=
code[
-
2
];
if
int
(sex)
%
2
=
=
0
:
print
(
"性别为女"
);
else
:
print
(
"性别为男"
)
|
网址观察与批量生成
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2
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for
i
in
range
(
2
,
16
):
print
(
'http://news.gzcc.cn/html/xiaoyuanxinwen/'
+
str
(i)
+
'.html'
)
|
凯撒密码编码与解码
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def
encryption():
str_raw
=
input
(
"请输入明文:"
)
k
=
int
(
input
(
"请输入位移值:"
))
str_change
=
str_raw.lower()
str_list
=
list
(str_change)
str_list_encry
=
str_list
i
=
0
while
i <
len
(str_list):
if
ord
(str_list[i]) <
123
-
k:
str_list_encry[i]
=
chr
(
ord
(str_list[i])
+
k)
else
:
str_list_encry[i]
=
chr
(
ord
(str_list[i])
+
k
-
26
)
i
=
i
+
1
print
(
"加密结果为:"
+
"".join(str_list_encry))
def
decryption():
str_raw
=
input
(
"请输入密文:"
)
k
=
int
(
input
(
"请输入位移值:"
))
str_change
=
str_raw.lower()
str_list
=
list
(str_change)
str_list_decry
=
str_list
i
=
0
while
i <
len
(str_list):
if
ord
(str_list[i]) >
=
97
+
k:
str_list_decry[i]
=
chr
(
ord
(str_list[i])
-
k)
else
:
str_list_decry[i]
=
chr
(
ord
(str_list[i])
+
26
-
k)
i
=
i
+
1
print
(
"解密结果为:"
+
"".join(str_list_decry))
while
True
:
print
(u
"1. 加密"
)
print
(u
"2. 解密"
)
choice
=
input
(
"请选择:"
)
if
choice
=
=
"1"
:
encryption()
elif
choice
=
=
"2"
:
decryption()
else
:
print
(u
"您的输入有误!"
)
|
2.英文词频统计预处理
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url
=
'''
WHEN MINUTES BECOME HOURS
WHEN DAYS BECOME YEARS
AND I DON’T KNOW WHERE YOU ARE
COLOR SEEMS SO DULL WITHOUT YOU
'''
str1
=
url.lower()
str2
=
str1.replace(
","
,"")
str3
=
str2.replace(
"'"
,"")
print
(str3)
print
(str3.split());
print
(str3.count(
'we'
))
|
3.文件操作
- 凯撒密码:从文件读入密函,进行加密或解密,保存到文件。
- 词频统计:下载一首英文的歌词或文章或小说,保存为utf8文件。从文件读入文本进行处理。
凯撒密码
词频统计
text=open('gril.txt','r',encoding='utf-8')
text=text.read()
x=",?!."
for xx in x:
text1=text.replace(xx,' ')
print(text1)
text2=open('gril1.txt','a',encoding='utf-8')
text2.write(text1)
4.函数定义
- 加密函数
def encryption(): str_raw = input("请输入明文:") k = int(input("请输入位移值:")) str_change = str_raw.lower() str_list = list(str_change) str_list_encry = str_list i = 0 while i < len(str_list): if ord(str_list[i]) < 123-k: str_list_encry[i] = chr(ord(str_list[i]) + k) else: str_list_encry[i] = chr(ord(str_list[i]) + k - 26) i = i+1 print ("加密结果为:"+"".join(str_list_encry))
- 解密函数
def decryption(): str_raw = input("请输入密文:") k = int(input("请输入位移值:")) str_change = str_raw.lower() str_list = list(str_change) str_list_decry = str_list i = 0 while i < len(str_list): if ord(str_list[i]) >= 97+k: str_list_decry[i] = chr(ord(str_list[i]) - k) else: str_list_decry[i] = chr(ord(str_list[i]) + 26 - k) i = i+1 print ("解密结果为:"+"".join(str_list_decry))
- 读文本函数
def readFile(filePath): file=open(filePath,'r',encoding='utf-8') return file.read()