52进制 java,Java实现的26进制转换
今天看到有个羣聊里分享了一道面试题，感觉挺有意思的就尝试了一下，代码如下：
public class Hex26 {
// 进制基础值，也可以修改为'a'
private final static char A = 'A';
public static void main(String[] args) {
int[] arr = {
0, 1, 2,
25, 26, 27,
51, 52, 53,
77, 78, 79
};
for (int i : arr) {
String str = toHex26(i);
System.out.printf("old: %d, str: %s, int: %d \n", i, str, compareHex26(str));
}
}
private static String toHex26(int i) {
StringBuilder sb = new StringBuilder();
if (i == 0) {
sb.append(A);
return sb.toString();
}
int divide = i / 26;
if (divide > 0) {
for (int j = 0; j < divide; j++) {
sb.append(A);
}
}
int m = i % 26;
char c = (char)(A + m);
sb.append(c);
return sb.toString();
}
private static int compareHex26(String hex) {
int i = 0, j = 0;
for (; j < hex.length() - 1; j++) {
char c = hex.charAt(j);
int diff = c - A;
if (diff == 0) {
i += 26;
}else {
i += diff;
}
}
if (j == hex.length()-1) {
char c = hex.charAt(j);
i += c - A;
}
return i;
}
}
输出结果如下：
old: 0, str: A, int: 0
old: 1, str: B, int: 1
old: 2, str: C, int: 2
old: 25, str: Z, int: 25
old: 26, str: AA, int: 26
old: 27, str: AB, int: 27
old: 51, str: AZ, int: 51
old: 52, str: AAA, int: 52
old: 53, str: AAB, int: 53
old: 77, str: AAZ, int: 77
old: 78, str: AAAA, int: 78
old: 79, str: AAAB, int: 79
over~