flask之文件上传
1、创建表单提交页面，如：upload.html
<html>
<head><title>File Upload</title>
</head>
<body><form action="http://localhost:8888/uploadfile" method="POST" enctype="multipart/form-data"><input type="file" name="file001" /><input type="submit" value="提交" /></form>
</body>
</html>
2、url地址关联表单提交页面
@app.route('/upload')
def uploadFile():return render_template('upload.html')
3、提交表单后定义执行保存的函数
@app.route('/uploadfile',methods=['GET','POST'])
def save():if request.method == 'POST':f = request.files['file001'] #提取文件f.save(os.path.join(app.config['UPLOAD_FOLDER'], secure_filename(f.filename)))
4、完整演示代码
from flask import Flask, render_template, request
from werkzeug.utils import secure_filenameimport osapp = Flask(__name__)
app.config['UPLOAD_FOLDER'] = 'upload/' #app.config['UPLOAD_FOLDER'] 定义上传文件夹的路径 @app.route('/upload')
def uploadFile():return render_template('upload.html')@app.route('/uploadfile',methods=['GET','POST'])
def save():if request.method == 'POST':f = request.files['file001'] #提取文件f.save(os.path.join(app.config['UPLOAD_FOLDER'], secure_filename(f.filename))) #保存文件，目标文件的名称可以是硬编码的，也可以从 request.files[file] 对象的 filename 属性中获取。但是，建议使用 secure_filename() 函数获取它的安全版本。return 'file uploaded successfully'else:return render_template('upload.html')if __name__ == '__main__':app.run(debug=True)