leetcode最大连续1的个数（简单）
比较简单，但解时候如果能一次通过更好
方案一
public int findMaxConsecutiveOnes(int[] nums) {int i = -1,j = 0,max = 0;while(j < nums.length && max < nums.length - i) {if(nums[j] != 1) {i = j;} else if(max < j - i){max = j - i;}j++;}return max;}方案二
public int findMaxConsecutiveOnes(int[] nums) {int i = -1,count = 0,max = 0;while(++i < nums.length) {if(nums[i] == 0) {count = 0;} else {count++;}if(max < count) max = count; }return max;}