import itertools
import random
import re
# 计算出结果的函数
def solution(data):
for i in itertools.permutations(data):
for j in itertools.product(['+', '-', '*', '/'], repeat=3):
li = [
f'(({i[0]}{j[0]}{i[1]}){j[1]}{i[2]}){j[2]}{i[3]}',
f'({i[0]}{j[0]}{i[1]}){j[1]}({i[2]}{j[2]}{i[3]})',
f'({i[0]}{j[0]}({i[1]}{j[1]}{i[2]})){j[2]}{i[3]}',
f'{i[0]}{j[0]}(({i[1]}{j[1]}{i[2]}){j[2]}{i[3]})',
f'{i[0]}{j[0]}({i[1]}{j[1]}({i[2]}{j[2]}{i[3]}))'
]
for k in li:
try:
if eval(k) == 24:
print(f'{k}=24')
return True
except ZeroDivisionError:
pass
return False
#机器给人出题
def A2():
poke = [str(random.randint(1, 13)), str(random.randint(1, 13)),
str(random.randint(1, 13)), str(random.randint(1, 13))]
poke = sorted(poke)
print(poke)
expr = input("输入运算式：")
li = re.split('[\+\-\*\/\(\)]', expr)
li = sorted(li)[-4:]
if len(li) == 4:
if li == poke:
if eval(expr) == 24:
print("正确！")
else:
print('错误！')
else:
print("检测到错误，exit")
else:
print("请遵守规则")
#人给机器出题
def A1():
print("规则：\n一、输入四个1-13的数字\n二、各个数字之间要使用空格")
print("请给机器出题：")
topic = input().split()
for i in topic:
i = int(i)
if 1 <= i <= 13:
topic = sorted(topic)
flag = solution(topic)
if flag:
print("\n得出")
break
elif not flag:
print("无法得出")
break
else:
print("请输入1-13的数字")
break
#框架
while True:
print("1.给机器出题")
print("2.机器出题")
print("3.退出")
print("选择序号：")
cmd = input()
while True:
if cmd == '1' or '2' or '3':
break
else:
print("数据不规范，请重新输入！")
if cmd == '1':
A1()
elif cmd == '2':
A2()
elif cmd == '3':
break
else:
pass
input("按回车退出")
