shell 脚本计算距离最近的坐标
shell 脚本计算距离最近的坐标
坐标数据文件geo.log格式如下：
beijing(116.405285,39.904989)
tinajin(117.190182,39.125596)
hebei(114.502461,38.045474)
shanxi(112.549248,37.857014)
neimenggu(111.670801,40.818311)
liaoning(123.429096,41.796767)
jilin(125.3245,43.886841)
heilongjiang(126.642464,45.756967)
shanghai1(121.472644,31.231706)
jiangsu(118.767413,32.041544)
zhejiang(120.153576,30.287459)
anhui(117.283042,31.86119)
fujian(119.306239,26.075302)
jiangxi(115.892151,28.676493)
shandong(117.000923,36.675807)
henan(113.665412,34.757975)
hubei(114.298572,30.584355)
hunan(112.982279,28.19409)
guangdong(113.280637,23.125178)
guangxi(108.320004,22.82402)
hainan(110.33119,20.031971)
chongqing(106.504962,29.533155)
sichuan(104.065735,30.659462)
guizhou(106.713478,26.578343)
yunnan(102.712251,25.040609)
xizang(91.132212,29.660361)
shanxi3(108.948024,34.263161)
gansu(103.823557,36.058039)
qinghai(101.778916,36.623178)
ningxia(106.278179,38.46637)
xinjiang(87.617733,43.792818)
taiwan(121.509062,25.044332)
xianggang(114.173355,22.320048)
aomen(113.54909,22.198951)编写脚本文件
coordinate.sh
#!/bin/bash# 计算两点之间的距离
function distance {x1=$1y1=$2x2=$3y2=$4echo "scale=2; sqrt(($x2 - $x1)^2 + ($y2 - $y1)^2)" | bc
}# 检查参数是否传入
if [ -z "$1" ] || [ -z "$2" ]; thenecho "Usage: $0 <coordinates file> <point name>"exit 1
fi# 从文件中读取坐标点并计算最近的点
while IFS='(' read -r name rest; doname=$(echo $name | tr -d ' ') # 去除空格rest=$(echo $rest | tr -d ')') # 去除右括号IFS=',' read -r x y <<< "$rest"if [ "$name" = "$2" ]; thenxA=$xyA=$yelsedist=$(distance $xA $yA $x $y)if [ -z "$minDistance" ] || (( $(echo "$dist < $minDistance" | bc -l) )); thenminDistance=$distclosestPoint=$namefifi
done < "$1" # 从传入的文件中读取坐标点echo "距离 $2 最近的点是 $closestPoint，距离为 $minDistance"
执行脚本文件
coordinate.sh
