2019独角兽企业重金招聘Python工程师标准>>> 
public boolean isAnagram(String s, String t) {
int[] alphabet = new int[26];
for (int i = 0; i < s.length(); i++) alphabet[s.charAt(i) - 'a']++;
for (int i = 0; i < t.length(); i++) alphabet[t.charAt(i) - 'a']--;
for (int i : alphabet) if (i != 0) return false;
return true;
}